How do I get a variable in a function to retain its value between calls?
<?php
function myfunc() { static $myfunctionvariable = 1;
echo "the number $myfunctionvariable\n";
$myfunctionvariable++;
}
myfunc(); //1
myfunc();//2
myfunc();//3
?>
The use of the static keyword means that it will only be assigned the value 1 once, so each time the function is called the number will increment by one. If you do not use the static keyword, each time the function is called the variable will be set back to 1 each time.
Copy the code and try calling the function a few times both with and without the static keyword to see the effect it has.
Comment on this Question and Answer >>>
ASK A QUESTION
More functions PHP Questions
mail1-what is a header("Location:http//www.website.com"); 2-how does it work? 3-What is a reason to use this function?
how can we display a particular data from database by creating a function
How can I call online a PHP function. It works local but when I put it online it does nothing. I call online a php function to load pictures into my flex application. Thanks Bart
How do I make a variable from outside a function work in that function?
